Base | Representation |
---|---|
bin | 1000010001110000001… |
… | …1010010000111001001 |
3 | 111121001110221021210222 |
4 | 2010130003102013021 |
5 | 4312213330342213 |
6 | 145154452515425 |
7 | 13162650450431 |
oct | 2043403220711 |
9 | 447043837728 |
10 | 142204543433 |
11 | 55343837267 |
12 | 2368801bb75 |
13 | 10543524674 |
14 | 6c5032d2c1 |
15 | 3a74539808 |
hex | 211c0d21c9 |
142204543433 has 4 divisors (see below), whose sum is σ = 142424334720. Its totient is φ = 141984752148.
The previous prime is 142204543381. The next prime is 142204543519. The reversal of 142204543433 is 334345402241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 142204543433 - 222 = 142200349129 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 142204543393 and 142204543402.
It is not an unprimeable number, because it can be changed into a prime (142204543133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109894673 + ... + 109895966.
It is an arithmetic number, because the mean of its divisors is an integer number (35606083680).
Almost surely, 2142204543433 is an apocalyptic number.
It is an amenable number.
142204543433 is a deficient number, since it is larger than the sum of its proper divisors (219791287).
142204543433 is an equidigital number, since it uses as much as digits as its factorization.
142204543433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 219791286.
The product of its (nonzero) digits is 138240, while the sum is 35.
Adding to 142204543433 its reverse (334345402241), we get a palindrome (476549945674).
The spelling of 142204543433 in words is "one hundred forty-two billion, two hundred four million, five hundred forty-three thousand, four hundred thirty-three".
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