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1422265004113 is a prime number
BaseRepresentation
bin10100101100100101100…
…110011011000001010001
312000222010002112012020211
4110230211212123001101
5141300244320112423
63005213551004121
7204520024031332
oct24544546330121
95028102465224
101422265004113
114a91a7575438
121ab789809641
13a4171622a15
144cba3650289
1526ee2b8810d
hex14b2599b051

1422265004113 has 2 divisors, whose sum is σ = 1422265004114. Its totient is φ = 1422265004112.

The previous prime is 1422265004059. The next prime is 1422265004119. The reversal of 1422265004113 is 3114005622241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1418319028624 + 3945975489 = 1190932^2 + 62817^2 .

It is a cyclic number.

It is not a de Polignac number, because 1422265004113 - 217 = 1422264873041 is a prime.

It is not a weakly prime, because it can be changed into another prime (1422265004119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711132502056 + 711132502057.

It is an arithmetic number, because the mean of its divisors is an integer number (711132502057).

Almost surely, 21422265004113 is an apocalyptic number.

It is an amenable number.

1422265004113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1422265004113 is an equidigital number, since it uses as much as digits as its factorization.

1422265004113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

The spelling of 1422265004113 in words is "one trillion, four hundred twenty-two billion, two hundred sixty-five million, four thousand, one hundred thirteen".