Base | Representation |
---|---|
bin | 1100111011111000110110… |
… | …0010110100111010010011 |
3 | 1212100201002010021121112010 |
4 | 3032332031202310322103 |
5 | 3331012211411343011 |
6 | 50125543344034003 |
7 | 2665402324305603 |
oct | 316761542647223 |
9 | 55321063247463 |
10 | 14223011434131 |
11 | 4593a44185945 |
12 | 1718621902903 |
13 | 7c22bb806826 |
14 | 37257c776c03 |
15 | 199e8e6901a6 |
hex | cef8d8b4e93 |
14223011434131 has 32 divisors (see below), whose sum is σ = 19614271392000. Its totient is φ = 9162557758080.
The previous prime is 14223011434117. The next prime is 14223011434193. The reversal of 14223011434131 is 13143411032241.
It is not a de Polignac number, because 14223011434131 - 27 = 14223011434003 is a prime.
It is a super-2 number, since 2×142230114341312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14223011434631) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16299340 + ... + 17149766.
It is an arithmetic number, because the mean of its divisors is an integer number (612945981000).
Almost surely, 214223011434131 is an apocalyptic number.
14223011434131 is a deficient number, since it is larger than the sum of its proper divisors (5391259957869).
14223011434131 is a wasteful number, since it uses less digits than its factorization.
14223011434131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 852099.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 14223011434131 its reverse (13143411032241), we get a palindrome (27366422466372).
The spelling of 14223011434131 in words is "fourteen trillion, two hundred twenty-three billion, eleven million, four hundred thirty-four thousand, one hundred thirty-one".
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