1422311131 has 2 divisors, whose sum is σ = 1422311132. Its totient is φ = 1422311130.

The previous prime is 1422311113. The next prime is 1422311141. The reversal of 1422311131 is 1311132241.

Together with previous prime (1422311113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1422311131 - 2¹³ = 1422302939 is a prime.

It is a super-2 number, since 2×1422311131² = 4045937906732998322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1422311099 and 1422311108.

It is not a weakly prime, because it can be changed into another prime (1422311141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711155565 + 711155566.

It is an arithmetic number, because the mean of its divisors is an integer number (711155566).

Almost surely, 2^1422311131 is an apocalyptic number.

1422311131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1422311131 is an equidigital number, since it uses as much as digits as its factorization.

1422311131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 19.

The square root of 1422311131 is about 37713.5404198545. The cubic root of 1422311131 is about 1124.6003205080.

Adding to 1422311131 its reverse (1311132241), we get a palindrome (2733443372).

The spelling of 1422311131 in words is "one billion, four hundred twenty-two million, three hundred eleven thousand, one hundred thirty-one".