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142231210600651 = 1021139305789031
BaseRepresentation
bin100000010101101111001000…
…110010001010100011001011
3200122121011121121121212022221
4200111233020302022203023
5122120304004403210101
61222300041025354511
741646602663336014
oct4025571062124313
9618534547555287
10142231210600651
1141356a10473467
1213b51440798a37
1361494653c2573
14271a054d9600b
151169b60998aa1
hex815bc8c8a8cb

142231210600651 has 4 divisors (see below), whose sum is σ = 142370516390704. Its totient is φ = 142091904810600.

The previous prime is 142231210600639. The next prime is 142231210600679. The reversal of 142231210600651 is 156006012132241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142231210600651 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142231210600681) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69652893495 + ... + 69652895536.

It is an arithmetic number, because the mean of its divisors is an integer number (35592629097676).

Almost surely, 2142231210600651 is an apocalyptic number.

142231210600651 is a deficient number, since it is larger than the sum of its proper divisors (139305790053).

142231210600651 is a wasteful number, since it uses less digits than its factorization.

142231210600651 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139305790052.

The product of its (nonzero) digits is 17280, while the sum is 34.

Adding to 142231210600651 its reverse (156006012132241), we get a palindrome (298237222732892).

The spelling of 142231210600651 in words is "one hundred forty-two trillion, two hundred thirty-one billion, two hundred ten million, six hundred thousand, six hundred fifty-one".

Divisors: 1 1021 139305789031 142231210600651