Base | Representation |
---|---|
bin | 1100111011111001101100… |
… | …1110111100101111100001 |
3 | 1212100201200010110001211122 |
4 | 3032332123032330233201 |
5 | 3331013144210314403 |
6 | 50130022230422025 |
7 | 2665411113416231 |
oct | 316763316745741 |
9 | 55321603401748 |
10 | 14223241104353 |
11 | 4594051893546 |
12 | 1718686801915 |
13 | 7c232727b978 |
14 | 3725a107dcc1 |
15 | 199ea490a838 |
hex | cef9b3bcbe1 |
14223241104353 has 2 divisors, whose sum is σ = 14223241104354. Its totient is φ = 14223241104352.
The previous prime is 14223241104341. The next prime is 14223241104533. The reversal of 14223241104353 is 35340114232241.
Together with next prime (14223241104533) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10108883225809 + 4114357878544 = 3179447^2 + 2028388^2 .
It is a cyclic number.
It is not a de Polignac number, because 14223241104353 - 24 = 14223241104337 is a prime.
It is not a weakly prime, because it can be changed into another prime (14223241104253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111620552176 + 7111620552177.
It is an arithmetic number, because the mean of its divisors is an integer number (7111620552177).
Almost surely, 214223241104353 is an apocalyptic number.
It is an amenable number.
14223241104353 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223241104353 is an equidigital number, since it uses as much as digits as its factorization.
14223241104353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 14223241104353 its reverse (35340114232241), we get a palindrome (49563355336594).
The spelling of 14223241104353 in words is "fourteen trillion, two hundred twenty-three billion, two hundred forty-one million, one hundred four thousand, three hundred fifty-three".
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