Base | Representation |
---|---|
bin | 1100111011111001111110… |
… | …0101000101000001100011 |
3 | 1212100201212012122021111022 |
4 | 3032332133211011001203 |
5 | 3331013321341424212 |
6 | 50130033353240055 |
7 | 2665412660222546 |
oct | 316763745050143 |
9 | 55321765567438 |
10 | 14223314014307 |
11 | 4594089a61902 |
12 | 17186a710302b |
13 | 7c23393c8b58 |
14 | 3725aaa1c85d |
15 | 199eab00d772 |
hex | cef9f945063 |
14223314014307 has 2 divisors, whose sum is σ = 14223314014308. Its totient is φ = 14223314014306.
The previous prime is 14223314014291. The next prime is 14223314014339. The reversal of 14223314014307 is 70341041332241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14223314014307 - 24 = 14223314014291 is a prime.
It is not a weakly prime, because it can be changed into another prime (14223314014807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111657007153 + 7111657007154.
It is an arithmetic number, because the mean of its divisors is an integer number (7111657007154).
Almost surely, 214223314014307 is an apocalyptic number.
14223314014307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223314014307 is an equidigital number, since it uses as much as digits as its factorization.
14223314014307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 14223314014307 its reverse (70341041332241), we get a palindrome (84564355346548).
The spelling of 14223314014307 in words is "fourteen trillion, two hundred twenty-three billion, three hundred fourteen million, fourteen thousand, three hundred seven".
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