Base | Representation |
---|---|
bin | 100000010101110001001011… |
… | …011010001010100010011010 |
3 | 200122121101021100100210210202 |
4 | 200111301023122022202122 |
5 | 122120323001420440232 |
6 | 1222301042313342202 |
7 | 41650011204103136 |
oct | 4025611332124232 |
9 | 618541240323722 |
10 | 142233402124442 |
11 | 41357935533752 |
12 | 13b51952707962 |
13 | 6149724446ac5 |
14 | 271a1c20683c6 |
15 | 1169c3d08e162 |
hex | 815c4b68a89a |
142233402124442 has 4 divisors (see below), whose sum is σ = 213350103186666. Its totient is φ = 71116701062220.
The previous prime is 142233402124433. The next prime is 142233402124501. The reversal of 142233402124442 is 244421204332241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 108249853853761 + 33983548270681 = 10404319^2 + 5829541^2 .
It is a super-2 number, since 2×1422334021244422 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 142233402124396 and 142233402124405.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35558350531109 + ... + 35558350531112.
Almost surely, 2142233402124442 is an apocalyptic number.
142233402124442 is a deficient number, since it is larger than the sum of its proper divisors (71116701062224).
142233402124442 is an equidigital number, since it uses as much as digits as its factorization.
142233402124442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71116701062223.
The product of its (nonzero) digits is 294912, while the sum is 38.
Adding to 142233402124442 its reverse (244421204332241), we get a palindrome (386654606456683).
The spelling of 142233402124442 in words is "one hundred forty-two trillion, two hundred thirty-three billion, four hundred two million, one hundred twenty-four thousand, four hundred forty-two".
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