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14223441343121 is a prime number
BaseRepresentation
bin1100111011111010011100…
…1010110011001010010001
31212100202012002020020210022
43032332213022303022101
53331014101440434441
650130054142313225
72665416064416563
oct316764712631221
955322162206708
1014223441343121
11459414491992a
121718721888815
137c23598ba84a
143725bd8c5333
15199eb72b084b
hexcefa72b3291

14223441343121 has 2 divisors, whose sum is σ = 14223441343122. Its totient is φ = 14223441343120.

The previous prime is 14223441343109. The next prime is 14223441343207. The reversal of 14223441343121 is 12134314432241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11337604842496 + 2885836500625 = 3367136^2 + 1698775^2 .

It is an emirp because it is prime and its reverse (12134314432241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14223441343121 - 242 = 9825394832017 is a prime.

It is not a weakly prime, because it can be changed into another prime (14223441363121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111720671560 + 7111720671561.

It is an arithmetic number, because the mean of its divisors is an integer number (7111720671561).

Almost surely, 214223441343121 is an apocalyptic number.

It is an amenable number.

14223441343121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14223441343121 is an equidigital number, since it uses as much as digits as its factorization.

14223441343121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 55296, while the sum is 35.

Adding to 14223441343121 its reverse (12134314432241), we get a palindrome (26357755775362).

The spelling of 14223441343121 in words is "fourteen trillion, two hundred twenty-three billion, four hundred forty-one million, three hundred forty-three thousand, one hundred twenty-one".