Base | Representation |
---|---|
bin | 1100111011111100100010… |
… | …1101010010001111001001 |
3 | 1212100210122022000210001011 |
4 | 3032333020231102033021 |
5 | 3331021230013001213 |
6 | 50130230042523521 |
7 | 2665436036245360 |
oct | 316771055221711 |
9 | 55323568023034 |
10 | 14224004031433 |
11 | 4594403502999 |
12 | 171885a2065a1 |
13 | 7c2419351401 |
14 | 3726345187d7 |
15 | 199eeb8ad03d |
hex | cefc8b523c9 |
14224004031433 has 8 divisors (see below), whose sum is σ = 16267380409280. Its totient is φ = 12183471604080.
The previous prime is 14224004031427. The next prime is 14224004031509. The reversal of 14224004031433 is 33413040042241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14224004031433 - 29 = 14224004030921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14224004031395 and 14224004031404.
It is not an unprimeable number, because it can be changed into a prime (14224004031403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 710976903 + ... + 710996908.
It is an arithmetic number, because the mean of its divisors is an integer number (2033422551160).
Almost surely, 214224004031433 is an apocalyptic number.
It is an amenable number.
14224004031433 is a deficient number, since it is larger than the sum of its proper divisors (2043376377847).
14224004031433 is a wasteful number, since it uses less digits than its factorization.
14224004031433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1421975247.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 14224004031433 its reverse (33413040042241), we get a palindrome (47637044073674).
The spelling of 14224004031433 in words is "fourteen trillion, two hundred twenty-four billion, four million, thirty-one thousand, four hundred thirty-three".
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