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14224004112113 = 125911297858707
BaseRepresentation
bin1100111011111100100010…
…1101100101111011110001
31212100210122022011212201022
43032333020231211323301
53331021230023041423
650130230044345225
72665436040032525
oct316771055457361
955323568155638
1014224004112113
114594403558574
12171885a245215
137c241937c053
14372634539d85
15199eeb8c6dc8
hexcefc8b65ef1

14224004112113 has 4 divisors (see below), whose sum is σ = 14235301972080. Its totient is φ = 14212706252148.

The previous prime is 14224004112091. The next prime is 14224004112179. The reversal of 14224004112113 is 31121140042241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14224004112113 - 238 = 13949126205169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14224004112413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5648928095 + ... + 5648930612.

It is an arithmetic number, because the mean of its divisors is an integer number (3558825493020).

Almost surely, 214224004112113 is an apocalyptic number.

It is an amenable number.

14224004112113 is a deficient number, since it is larger than the sum of its proper divisors (11297859967).

14224004112113 is a wasteful number, since it uses less digits than its factorization.

14224004112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11297859966.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 14224004112113 its reverse (31121140042241), we get a palindrome (45345144154354).

The spelling of 14224004112113 in words is "fourteen trillion, two hundred twenty-four billion, four million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 1259 11297858707 14224004112113