Base | Representation |
---|---|
bin | 1100111011111100100010… |
… | …1101100101111011110001 |
3 | 1212100210122022011212201022 |
4 | 3032333020231211323301 |
5 | 3331021230023041423 |
6 | 50130230044345225 |
7 | 2665436040032525 |
oct | 316771055457361 |
9 | 55323568155638 |
10 | 14224004112113 |
11 | 4594403558574 |
12 | 171885a245215 |
13 | 7c241937c053 |
14 | 372634539d85 |
15 | 199eeb8c6dc8 |
hex | cefc8b65ef1 |
14224004112113 has 4 divisors (see below), whose sum is σ = 14235301972080. Its totient is φ = 14212706252148.
The previous prime is 14224004112091. The next prime is 14224004112179. The reversal of 14224004112113 is 31121140042241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14224004112113 - 238 = 13949126205169 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14224004112413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5648928095 + ... + 5648930612.
It is an arithmetic number, because the mean of its divisors is an integer number (3558825493020).
Almost surely, 214224004112113 is an apocalyptic number.
It is an amenable number.
14224004112113 is a deficient number, since it is larger than the sum of its proper divisors (11297859967).
14224004112113 is a wasteful number, since it uses less digits than its factorization.
14224004112113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11297859966.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 14224004112113 its reverse (31121140042241), we get a palindrome (45345144154354).
The spelling of 14224004112113 in words is "fourteen trillion, two hundred twenty-four billion, four million, one hundred twelve thousand, one hundred thirteen".
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