Base | Representation |
---|---|
bin | 1100111011111100111001… |
… | …1011110111111001100011 |
3 | 1212100210212222212010001021 |
4 | 3032333032123313321203 |
5 | 3331021424113133103 |
6 | 50130243354350311 |
7 | 2665441314132322 |
oct | 316771633677143 |
9 | 55323788763037 |
10 | 14224100130403 |
11 | 459445277a529 |
12 | 171888642b397 |
13 | 7c243322a3c7 |
14 | 3726431b20b9 |
15 | 19a005041bbd |
hex | cefce6f7e63 |
14224100130403 has 2 divisors, whose sum is σ = 14224100130404. Its totient is φ = 14224100130402.
The previous prime is 14224100130367. The next prime is 14224100130413. The reversal of 14224100130403 is 30403100142241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14224100130403 - 229 = 14223563259491 is a prime.
It is not a weakly prime, because it can be changed into another prime (14224100130413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112050065201 + 7112050065202.
It is an arithmetic number, because the mean of its divisors is an integer number (7112050065202).
Almost surely, 214224100130403 is an apocalyptic number.
14224100130403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224100130403 is an equidigital number, since it uses as much as digits as its factorization.
14224100130403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14224100130403 its reverse (30403100142241), we get a palindrome (44627200272644).
The spelling of 14224100130403 in words is "fourteen trillion, two hundred twenty-four billion, one hundred million, one hundred thirty thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •