14224100141113 has 4 divisors (see below), whose sum is σ = 14608535280100. Its totient is φ = 13839665002128.

The previous prime is 14224100141093. The next prime is 14224100141117. The reversal of 14224100141113 is 31114100142241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8939310657424 + 5284789483689 = 2989868^2 + 2298867^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14224100141113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14224100141117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 192217569438 + ... + 192217569511.

It is an arithmetic number, because the mean of its divisors is an integer number (3652133820025).

Almost surely, 2^{14224100141113} is an apocalyptic number.

It is an amenable number.

14224100141113 is a deficient number, since it is larger than the sum of its proper divisors (384435138987).

14224100141113 is an equidigital number, since it uses as much as digits as its factorization.

14224100141113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 384435138986.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 14224100141113 its reverse (31114100142241), we get a palindrome (45338200283354).

The spelling of 14224100141113 in words is "fourteen trillion, two hundred twenty-four billion, one hundred million, one hundred forty-one thousand, one hundred thirteen".