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14224142044403 = 60723433512429
BaseRepresentation
bin1100111011111101000011…
…1011110000110011110011
31212100210222220201120020122
43032333100323300303303
53331022020330410103
650130251453000455
72665442333321504
oct316772073606363
955323886646218
1014224142044403
1145944743a80a5
12171889848312b
137c243bb141a5
143726489a2bab
1519a008a70b38
hexcefd0ef0cf3

14224142044403 has 4 divisors (see below), whose sum is σ = 14247575557440. Its totient is φ = 14200708531368.

The previous prime is 14224142044361. The next prime is 14224142044417. The reversal of 14224142044403 is 30444024142241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14224142044403 - 210 = 14224142043379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14224142044423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11716755608 + ... + 11716756821.

It is an arithmetic number, because the mean of its divisors is an integer number (3561893889360).

Almost surely, 214224142044403 is an apocalyptic number.

14224142044403 is a deficient number, since it is larger than the sum of its proper divisors (23433513037).

14224142044403 is an equidigital number, since it uses as much as digits as its factorization.

14224142044403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23433513036.

The product of its (nonzero) digits is 98304, while the sum is 35.

Adding to 14224142044403 its reverse (30444024142241), we get a palindrome (44668166186644).

The spelling of 14224142044403 in words is "fourteen trillion, two hundred twenty-four billion, one hundred forty-two million, forty-four thousand, four hundred three".

Divisors: 1 607 23433512429 14224142044403