Base | Representation |
---|---|
bin | 1100111011111101010010… |
… | …1000001001001010000001 |
3 | 1212100211011020022202012221 |
4 | 3032333110220021022001 |
5 | 3331022132211310423 |
6 | 50130301545051041 |
7 | 2665444015113526 |
oct | 316772450111201 |
9 | 55324136282187 |
10 | 14224204010113 |
11 | 45944a6380929 |
12 | 17188b5186a81 |
13 | 7c244b8cbaa6 |
14 | 372652cd314d |
15 | 19a00e210e5d |
hex | cefd4a09281 |
14224204010113 has 2 divisors, whose sum is σ = 14224204010114. Its totient is φ = 14224204010112.
The previous prime is 14224204010101. The next prime is 14224204010129. The reversal of 14224204010113 is 31101040242241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12317341294449 + 1906862715664 = 3509607^2 + 1380892^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14224204010113 is a prime.
It is not a weakly prime, because it can be changed into another prime (14224204010153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112102005056 + 7112102005057.
It is an arithmetic number, because the mean of its divisors is an integer number (7112102005057).
Almost surely, 214224204010113 is an apocalyptic number.
It is an amenable number.
14224204010113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224204010113 is an equidigital number, since it uses as much as digits as its factorization.
14224204010113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14224204010113 its reverse (31101040242241), we get a palindrome (45325244252354).
The spelling of 14224204010113 in words is "fourteen trillion, two hundred twenty-four billion, two hundred four million, ten thousand, one hundred thirteen".
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