Base | Representation |
---|---|
bin | 1100111011111101010111… |
… | …0000101000111000001011 |
3 | 1212100211012120002021012211 |
4 | 3032333111300220320023 |
5 | 3331022202042430121 |
6 | 50130303504245551 |
7 | 2665444335464614 |
oct | 316772560507013 |
9 | 55324176067184 |
10 | 14224223014411 |
11 | 4594506081063 |
12 | 17188bb6108b7 |
13 | 7c2452823c37 |
14 | 37265563cc0b |
15 | 19a010c16ce1 |
hex | cefd5c28e0b |
14224223014411 has 4 divisors (see below), whose sum is σ = 14384045745000. Its totient is φ = 14064400283824.
The previous prime is 14224223014343. The next prime is 14224223014439. The reversal of 14224223014411 is 11441032242241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14224223014411 - 213 = 14224223006219 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14224223614411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79911365161 + ... + 79911365338.
It is an arithmetic number, because the mean of its divisors is an integer number (3596011436250).
Almost surely, 214224223014411 is an apocalyptic number.
14224223014411 is a deficient number, since it is larger than the sum of its proper divisors (159822730589).
14224223014411 is an equidigital number, since it uses as much as digits as its factorization.
14224223014411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159822730588.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 14224223014411 its reverse (11441032242241), we get a palindrome (25665255256652).
The spelling of 14224223014411 in words is "fourteen trillion, two hundred twenty-four billion, two hundred twenty-three million, fourteen thousand, four hundred eleven".
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