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142300031400313 is a prime number
BaseRepresentation
bin100000010110101111001110…
…110100101011100101111001
3200122211202020212002201102221
4200112233032310223211321
5122122420431014302223
61222351422034124041
741654560301436553
oct4026571664534571
9618752225081387
10142300031400313
1141383116a758a6
1213b62848720621
136152ab2448b27
14271d5031344d3
15116b83c7cbb5d
hex816bced2b979

142300031400313 has 2 divisors, whose sum is σ = 142300031400314. Its totient is φ = 142300031400312.

The previous prime is 142300031400269. The next prime is 142300031400337. The reversal of 142300031400313 is 313004130003241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140619824372329 + 1680207027984 = 11858323^2 + 1296228^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142300031400313 is a prime.

It is not a weakly prime, because it can be changed into another prime (142300031460313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71150015700156 + 71150015700157.

It is an arithmetic number, because the mean of its divisors is an integer number (71150015700157).

Almost surely, 2142300031400313 is an apocalyptic number.

It is an amenable number.

142300031400313 is a deficient number, since it is larger than the sum of its proper divisors (1).

142300031400313 is an equidigital number, since it uses as much as digits as its factorization.

142300031400313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 142300031400313 its reverse (313004130003241), we get a palindrome (455304161403554).

The spelling of 142300031400313 in words is "one hundred forty-two trillion, three hundred billion, thirty-one million, four hundred thousand, three hundred thirteen".