Base | Representation |
---|---|
bin | 1100111100010011000010… |
… | …1111001100110110001010 |
3 | 1212101101020020220210212211 |
4 | 3033010300233030312022 |
5 | 3331121112322101102 |
6 | 50133105255255334 |
7 | 2666041523041354 |
oct | 317046057146612 |
9 | 55341206823784 |
10 | 14230044331402 |
11 | 4596a23059739 |
12 | 1719a6507a54a |
13 | 7c2b6c88a3c3 |
14 | 372a488180d4 |
15 | 19a251d067d7 |
hex | cf130bccd8a |
14230044331402 has 4 divisors (see below), whose sum is σ = 21345066497106. Its totient is φ = 7115022165700.
The previous prime is 14230044331397. The next prime is 14230044331411. The reversal of 14230044331402 is 20413344003241.
14230044331402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12612647942041 + 1617396389361 = 3551429^2 + 1271769^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3557511082849 + ... + 3557511082852.
Almost surely, 214230044331402 is an apocalyptic number.
14230044331402 is a deficient number, since it is larger than the sum of its proper divisors (7115022165704).
14230044331402 is an equidigital number, since it uses as much as digits as its factorization.
14230044331402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7115022165703.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 14230044331402 its reverse (20413344003241), we get a palindrome (34643388334643).
The spelling of 14230044331402 in words is "fourteen trillion, two hundred thirty billion, forty-four million, three hundred thirty-one thousand, four hundred two".
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