Base | Representation |
---|---|
bin | 10100101101010010010… |
… | …000100100011001000011 |
3 | 12001001001022100211110101 |
4 | 110231102100210121003 |
5 | 141303313122000201 |
6 | 3005420153543231 |
7 | 204544422356662 |
oct | 24552220443103 |
9 | 5031038324411 |
10 | 1423014250051 |
11 | 4a955149aa59 |
12 | 1ab958714b17 |
13 | a4260915204 |
14 | 4cc34d66dd9 |
15 | 27038836d01 |
hex | 14b52424643 |
1423014250051 has 2 divisors, whose sum is σ = 1423014250052. Its totient is φ = 1423014250050.
The previous prime is 1423014249959. The next prime is 1423014250057. The reversal of 1423014250051 is 1500524103241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1423014250051 - 223 = 1423005861443 is a prime.
It is not a weakly prime, because it can be changed into another prime (1423014250057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711507125025 + 711507125026.
It is an arithmetic number, because the mean of its divisors is an integer number (711507125026).
Almost surely, 21423014250051 is an apocalyptic number.
1423014250051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1423014250051 is an equidigital number, since it uses as much as digits as its factorization.
1423014250051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 1423014250051 its reverse (1500524103241), we get a palindrome (2923538353292).
The spelling of 1423014250051 in words is "one trillion, four hundred twenty-three billion, fourteen million, two hundred fifty thousand, fifty-one".
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