Base | Representation |
---|---|
bin | 100000010110111001100010… |
… | …101001000111001001010011 |
3 | 200122212210211100010102011212 |
4 | 200112321202221013021103 |
5 | 122123111113420030003 |
6 | 1222400452321130335 |
7 | 41655431520334214 |
oct | 4026714251071123 |
9 | 618783740112155 |
10 | 142311101330003 |
11 | 41387887726921 |
12 | 13b64a17a899ab |
13 | 6153b579b8c98 |
14 | 271dc7340940b |
15 | 116bc89580dd8 |
hex | 816e62a47253 |
142311101330003 has 32 divisors (see below), whose sum is σ = 161707530124800. Its totient is φ = 124509977577216.
The previous prime is 142311101329981. The next prime is 142311101330033. The reversal of 142311101330003 is 300033101113241.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142311101330003 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (142311101330033) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1071093551 + ... + 1071226407.
It is an arithmetic number, because the mean of its divisors is an integer number (5053360316400).
Almost surely, 2142311101330003 is an apocalyptic number.
142311101330003 is a deficient number, since it is larger than the sum of its proper divisors (19396428794797).
142311101330003 is a wasteful number, since it uses less digits than its factorization.
142311101330003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 217451.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 142311101330003 its reverse (300033101113241), we get a palindrome (442344202443244).
The spelling of 142311101330003 in words is "one hundred forty-two trillion, three hundred eleven billion, one hundred one million, three hundred thirty thousand, three".
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