Base | Representation |
---|---|
bin | 1100111100010111011001… |
… | …0001110100001011011011 |
3 | 1212101111020120021102000111 |
4 | 3033011312101310023123 |
5 | 3331131010011031212 |
6 | 50133421133545151 |
7 | 2666112450613552 |
oct | 317056621641333 |
9 | 55344216242014 |
10 | 14231211033307 |
11 | 4597471692094 |
12 | 171a12b9451b7 |
13 | 7c2cc74c3668 |
14 | 372b1975ad99 |
15 | 19a2be465ea7 |
hex | cf1764742db |
14231211033307 has 2 divisors, whose sum is σ = 14231211033308. Its totient is φ = 14231211033306.
The previous prime is 14231211033293. The next prime is 14231211033313. The reversal of 14231211033307 is 70333011213241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14231211033307 is a prime.
It is not a weakly prime, because it can be changed into another prime (14231211033407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115605516653 + 7115605516654.
It is an arithmetic number, because the mean of its divisors is an integer number (7115605516654).
Almost surely, 214231211033307 is an apocalyptic number.
14231211033307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14231211033307 is an equidigital number, since it uses as much as digits as its factorization.
14231211033307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 14231211033307 its reverse (70333011213241), we get a palindrome (84564222246548).
The spelling of 14231211033307 in words is "fourteen trillion, two hundred thirty-one billion, two hundred eleven million, thirty-three thousand, three hundred seven".
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