14231211333331 has 2 divisors, whose sum is σ = 14231211333332. Its totient is φ = 14231211333330.

The previous prime is 14231211333319. The next prime is 14231211333337. The reversal of 14231211333331 is 13333311213241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14231211333331 - 2¹¹ = 14231211331283 is a prime.

It is a super-2 number, since 2×14231211333331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14231211333293 and 14231211333302.

It is not a weakly prime, because it can be changed into another prime (14231211333337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115605666665 + 7115605666666.

It is an arithmetic number, because the mean of its divisors is an integer number (7115605666666).

Almost surely, 2^{14231211333331} is an apocalyptic number.

14231211333331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14231211333331 is an equidigital number, since it uses as much as digits as its factorization.

14231211333331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11664, while the sum is 31.

Adding to 14231211333331 its reverse (13333311213241), we get a palindrome (27564522546572).

The spelling of 14231211333331 in words is "fourteen trillion, two hundred thirty-one billion, two hundred eleven million, three hundred thirty-three thousand, three hundred thirty-one".