Base | Representation |
---|---|
bin | 100000010111000010110001… |
… | …011001000000100001110011 |
3 | 200122220202102001122010121022 |
4 | 200113002301121000201303 |
5 | 122123241413141141001 |
6 | 1222405212010450055 |
7 | 41656232235401135 |
oct | 4027026131004163 |
9 | 618822361563538 |
10 | 142321012443251 |
11 | 4139100324aa04 |
12 | 13b6692313392b |
13 | 6154a77154135 |
14 | 2720533831055 |
15 | 116c16973211b |
hex | 8170b1640873 |
142321012443251 has 4 divisors (see below), whose sum is σ = 142322369058672. Its totient is φ = 142319655827832.
The previous prime is 142321012443223. The next prime is 142321012443271. The reversal of 142321012443251 is 152344210123241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 142321012443251 - 218 = 142321012181107 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (142321012443271) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 678150335 + ... + 678360168.
It is an arithmetic number, because the mean of its divisors is an integer number (35580592264668).
Almost surely, 2142321012443251 is an apocalyptic number.
142321012443251 is a deficient number, since it is larger than the sum of its proper divisors (1356615421).
142321012443251 is a wasteful number, since it uses less digits than its factorization.
142321012443251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1356615420.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 142321012443251 its reverse (152344210123241), we get a palindrome (294665222566492).
The spelling of 142321012443251 in words is "one hundred forty-two trillion, three hundred twenty-one billion, twelve million, four hundred forty-three thousand, two hundred fifty-one".
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