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142321023413651 is a prime number
BaseRepresentation
bin100000010111000010110010…
…000010110110110110010011
3200122220202102211021111011102
4200113002302002312312103
5122123241423443214101
61222405213041535015
741656232430551615
oct4027026202666623
9618822384244142
10142321023413651
1141391009463155
1213b6692694446b
136154a794c55b4
142720535088db5
15116c16a69c86b
hex8170b20b6d93

142321023413651 has 2 divisors, whose sum is σ = 142321023413652. Its totient is φ = 142321023413650.

The previous prime is 142321023413629. The next prime is 142321023413671. The reversal of 142321023413651 is 156314320123241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142321023413651 is a prime.

It is a super-2 number, since 2×1423210234136512 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (142321023413671) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71160511706825 + 71160511706826.

It is an arithmetic number, because the mean of its divisors is an integer number (71160511706826).

Almost surely, 2142321023413651 is an apocalyptic number.

142321023413651 is a deficient number, since it is larger than the sum of its proper divisors (1).

142321023413651 is an equidigital number, since it uses as much as digits as its factorization.

142321023413651 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 38.

Adding to 142321023413651 its reverse (156314320123241), we get a palindrome (298635343536892).

The spelling of 142321023413651 in words is "one hundred forty-two trillion, three hundred twenty-one billion, twenty-three million, four hundred thirteen thousand, six hundred fifty-one".