Base | Representation |
---|---|
bin | 100000010111000100111011… |
… | …110011000111011111100011 |
3 | 200122220222101220002001001222 |
4 | 200113010323303013133203 |
5 | 122123311142120341311 |
6 | 1222410234241245255 |
7 | 41656343623046204 |
oct | 4027047363073743 |
9 | 618828356061058 |
10 | 142323334543331 |
11 | 41391a94a96087 |
12 | 13b6727093382b |
13 | 6155057266556 |
14 | 27206b3db35ab |
15 | 116c25351badb |
hex | 81713bcc77e3 |
142323334543331 has 2 divisors, whose sum is σ = 142323334543332. Its totient is φ = 142323334543330.
The previous prime is 142323334543303. The next prime is 142323334543367. The reversal of 142323334543331 is 133345433323241.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142323334543331 is a prime.
It is a super-2 number, since 2×1423233345433312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (142323334543391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71161667271665 + 71161667271666.
It is an arithmetic number, because the mean of its divisors is an integer number (71161667271666).
Almost surely, 2142323334543331 is an apocalyptic number.
142323334543331 is a deficient number, since it is larger than the sum of its proper divisors (1).
142323334543331 is an equidigital number, since it uses as much as digits as its factorization.
142323334543331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2799360, while the sum is 44.
Adding to 142323334543331 its reverse (133345433323241), we get a palindrome (275668767866572).
The spelling of 142323334543331 in words is "one hundred forty-two trillion, three hundred twenty-three billion, three hundred thirty-four million, five hundred forty-three thousand, three hundred thirty-one".
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