142323515543491 has 2 divisors, whose sum is σ = 142323515543492. Its totient is φ = 142323515543490.

The previous prime is 142323515543371. The next prime is 142323515543513. The reversal of 142323515543491 is 194345515323241.

It is a strong prime.

It is an emirp because it is prime and its reverse (194345515323241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142323515543491 is a prime.

It is a super-3 number, since 3×142323515543491³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (142323515540491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71161757771745 + 71161757771746.

It is an arithmetic number, because the mean of its divisors is an integer number (71161757771746).

Almost surely, 2^{142323515543491} is an apocalyptic number.

142323515543491 is a deficient number, since it is larger than the sum of its proper divisors (1).

142323515543491 is an equidigital number, since it uses as much as digits as its factorization.

142323515543491 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7776000, while the sum is 52.

The spelling of 142323515543491 in words is "one hundred forty-two trillion, three hundred twenty-three billion, five hundred fifteen million, five hundred forty-three thousand, four hundred ninety-one".