Base | Representation |
---|---|
bin | 100000010111000101000111… |
… | …011101100001101100000011 |
3 | 200122220222220112020221100112 |
4 | 200113011013131201230003 |
5 | 122123312042213210201 |
6 | 1222410305511141535 |
7 | 41656351520145131 |
oct | 4027050735415403 |
9 | 618828815227315 |
10 | 142323530210051 |
11 | 41392085489413 |
12 | 13b673063748ab |
13 | 6155088964388 |
14 | 27206d1d88751 |
15 | 116c2657bc0bb |
hex | 817147761b03 |
142323530210051 has 8 divisors (see below), whose sum is σ = 142345945867104. Its totient is φ = 142301115816640.
The previous prime is 142323530210047. The next prime is 142323530210093. The reversal of 142323530210051 is 150012035323241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 142323530210051 - 22 = 142323530210047 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (142323530210551) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 239094671 + ... + 239689191.
It is an arithmetic number, because the mean of its divisors is an integer number (17793243233388).
Almost surely, 2142323530210051 is an apocalyptic number.
142323530210051 is a deficient number, since it is larger than the sum of its proper divisors (22415657053).
142323530210051 is an equidigital number, since it uses as much as digits as its factorization.
142323530210051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 631821.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 142323530210051 its reverse (150012035323241), we get a palindrome (292335565533292).
The spelling of 142323530210051 in words is "one hundred forty-two trillion, three hundred twenty-three billion, five hundred thirty million, two hundred ten thousand, fifty-one".
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