Base | Representation |
---|---|
bin | 100000010111001101000110… |
… | …011100010101010001110011 |
3 | 200122221211000222120120001002 |
4 | 200113031012130111101303 |
5 | 122123432121340220301 |
6 | 1222414244313032215 |
7 | 41660104125133442 |
oct | 4027150634252163 |
9 | 618854028516032 |
10 | 142332103054451 |
11 | 41395784647292 |
12 | 13b68ab93b566b |
13 | 6155b23a8597b |
14 | 2720ca676ad59 |
15 | 116c5b821e16b |
hex | 817346715473 |
142332103054451 has 2 divisors, whose sum is σ = 142332103054452. Its totient is φ = 142332103054450.
The previous prime is 142332103054381. The next prime is 142332103054459. The reversal of 142332103054451 is 154450301233241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142332103054451 is a prime.
It is a super-2 number, since 2×1423321030544512 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (142332103054459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71166051527225 + 71166051527226.
It is an arithmetic number, because the mean of its divisors is an integer number (71166051527226).
Almost surely, 2142332103054451 is an apocalyptic number.
142332103054451 is a deficient number, since it is larger than the sum of its proper divisors (1).
142332103054451 is an equidigital number, since it uses as much as digits as its factorization.
142332103054451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 142332103054451 its reverse (154450301233241), we get a palindrome (296782404287692).
The spelling of 142332103054451 in words is "one hundred forty-two trillion, three hundred thirty-two billion, one hundred three million, fifty-four thousand, four hundred fifty-one".
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