Base | Representation |
---|---|
bin | 1000010010001110110… |
… | …1101100010010111001 |
3 | 111121101102211200222021 |
4 | 2010203231230102321 |
5 | 4312444233214431 |
6 | 145215324154441 |
7 | 13166101253512 |
oct | 2044355542271 |
9 | 447342750867 |
10 | 142333101241 |
11 | 553aa363691 |
12 | 23703098a21 |
13 | 10564056886 |
14 | 6c63435a09 |
15 | 3a80980b11 |
hex | 2123b6c4b9 |
142333101241 has 4 divisors (see below), whose sum is σ = 142672798800. Its totient is φ = 141993403684.
The previous prime is 142333101167. The next prime is 142333101263. The reversal of 142333101241 is 142101333241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 142333101241 - 227 = 142198883513 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (142333101041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169848151 + ... + 169848988.
It is an arithmetic number, because the mean of its divisors is an integer number (35668199700).
Almost surely, 2142333101241 is an apocalyptic number.
It is an amenable number.
142333101241 is a deficient number, since it is larger than the sum of its proper divisors (339697559).
142333101241 is an equidigital number, since it uses as much as digits as its factorization.
142333101241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 339697558.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 142333101241 its reverse (142101333241), we get a palindrome (284434434482).
The spelling of 142333101241 in words is "one hundred forty-two billion, three hundred thirty-three million, one hundred one thousand, two hundred forty-one".
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