Base | Representation |
---|---|
bin | 10100101101100101010… |
… | …100011110101000101001 |
3 | 12001001212121002221202022 |
4 | 110231211110132220221 |
5 | 141304442003322103 |
6 | 3005512020114225 |
7 | 204555354511322 |
oct | 24554524365051 |
9 | 5031777087668 |
10 | 1423334042153 |
11 | 4a96a5a62551 |
12 | 1aba27835975 |
13 | a42b1c528ca |
14 | 4cc6560d449 |
15 | 27056955138 |
hex | 14b6551ea29 |
1423334042153 has 2 divisors, whose sum is σ = 1423334042154. Its totient is φ = 1423334042152.
The previous prime is 1423334042149. The next prime is 1423334042233. The reversal of 1423334042153 is 3512404333241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1277198337424 + 146135704729 = 1130132^2 + 382277^2 .
It is a cyclic number.
It is not a de Polignac number, because 1423334042153 - 22 = 1423334042149 is a prime.
It is not a weakly prime, because it can be changed into another prime (1423334045153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711667021076 + 711667021077.
It is an arithmetic number, because the mean of its divisors is an integer number (711667021077).
Almost surely, 21423334042153 is an apocalyptic number.
It is an amenable number.
1423334042153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1423334042153 is an equidigital number, since it uses as much as digits as its factorization.
1423334042153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 1423334042153 its reverse (3512404333241), we get a palindrome (4935738375394).
The spelling of 1423334042153 in words is "one trillion, four hundred twenty-three billion, three hundred thirty-four million, forty-two thousand, one hundred fifty-three".
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