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142334144241953 is a prime number
BaseRepresentation
bin100000010111001111000000…
…000110110110000100100001
3200122222000022020102121220012
4200113033000012312010201
5122124000311411220303
61222415223030454305
741660205532010426
oct4027170006660441
9618860266377805
10142334144241953
1141396631865704
1213b69388b04395
13615608a921221
14272101b8a7d4d
15116c68751a5d8
hex8173c01b6121

142334144241953 has 2 divisors, whose sum is σ = 142334144241954. Its totient is φ = 142334144241952.

The previous prime is 142334144241923. The next prime is 142334144242009. The reversal of 142334144241953 is 359142441433241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106547152220224 + 35786992021729 = 10322168^2 + 5982223^2 .

It is a cyclic number.

It is not a de Polignac number, because 142334144241953 - 218 = 142334143979809 is a prime.

It is not a weakly prime, because it can be changed into another prime (142334144241923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71167072120976 + 71167072120977.

It is an arithmetic number, because the mean of its divisors is an integer number (71167072120977).

Almost surely, 2142334144241953 is an apocalyptic number.

It is an amenable number.

142334144241953 is a deficient number, since it is larger than the sum of its proper divisors (1).

142334144241953 is an equidigital number, since it uses as much as digits as its factorization.

142334144241953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4976640, while the sum is 50.

The spelling of 142334144241953 in words is "one hundred forty-two trillion, three hundred thirty-four billion, one hundred forty-four million, two hundred forty-one thousand, nine hundred fifty-three".