Base | Representation |
---|---|
bin | 1100111100100001111010… |
… | …0010101111110001101101 |
3 | 1212101202112022021012200120 |
4 | 3033020132202233301231 |
5 | 3331202300203402023 |
6 | 50135005220515153 |
7 | 2666242430040510 |
oct | 317103642576155 |
9 | 55352468235616 |
10 | 14234034044013 |
11 | 4598690156893 |
12 | 171a79924bab9 |
13 | 7c33573194b4 |
14 | 372d06650d77 |
15 | 19a3d71e88e3 |
hex | cf21e8afc6d |
14234034044013 has 32 divisors (see below), whose sum is σ = 22846765440000. Its totient is φ = 7700501644416.
The previous prime is 14234034043967. The next prime is 14234034044057. The reversal of 14234034044013 is 31044043043241.
It is not a de Polignac number, because 14234034044013 - 221 = 14234031946861 is a prime.
It is a super-2 number, since 2×142340340440132 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14234034043013) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11301256 + ... + 12497457.
It is an arithmetic number, because the mean of its divisors is an integer number (713961420000).
Almost surely, 214234034044013 is an apocalyptic number.
It is an amenable number.
14234034044013 is a deficient number, since it is larger than the sum of its proper divisors (8612731395987).
14234034044013 is a wasteful number, since it uses less digits than its factorization.
14234034044013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23800241.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 14234034044013 its reverse (31044043043241), we get a palindrome (45278077087254).
The spelling of 14234034044013 in words is "fourteen trillion, two hundred thirty-four billion, thirty-four million, forty-four thousand, thirteen".
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