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14234140153 is a prime number
BaseRepresentation
bin11010100000110101…
…11011110111111001
31100202000001020111001
431100122323313321
5213122414441103
610312235005001
71012510123612
oct152032736771
940660036431
1014234140153
11604488a1a2
122912b99761
13145ac8a74c
14990624c09
1558498301d
hex3506bbdf9

14234140153 has 2 divisors, whose sum is σ = 14234140154. Its totient is φ = 14234140152.

The previous prime is 14234140139. The next prime is 14234140159. The reversal of 14234140153 is 35104143241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13398525504 + 835614649 = 115752^2 + 28907^2 .

It is a cyclic number.

It is not a de Polignac number, because 14234140153 - 29 = 14234139641 is a prime.

It is a super-2 number, since 2×142341401532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14234140159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117070076 + 7117070077.

It is an arithmetic number, because the mean of its divisors is an integer number (7117070077).

Almost surely, 214234140153 is an apocalyptic number.

It is an amenable number.

14234140153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14234140153 is an equidigital number, since it uses as much as digits as its factorization.

14234140153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 14234140153 its reverse (35104143241), we get a palindrome (49338283394).

The spelling of 14234140153 in words is "fourteen billion, two hundred thirty-four million, one hundred forty thousand, one hundred fifty-three".