Base | Representation |
---|---|
bin | 1100111100100010101001… |
… | …1101100111000111011011 |
3 | 1212101210001020120021012222 |
4 | 3033020222131213013123 |
5 | 3331203202402240121 |
6 | 50135041123054255 |
7 | 2666250405613652 |
oct | 317105235470733 |
9 | 55353036507188 |
10 | 14234234024411 |
11 | 4598783026045 |
12 | 171a83421138b |
13 | 7c33898978ab |
14 | 372d2502a199 |
15 | 19a3e9a4c0ab |
hex | cf22a7671db |
14234234024411 has 2 divisors, whose sum is σ = 14234234024412. Its totient is φ = 14234234024410.
The previous prime is 14234234024401. The next prime is 14234234024467. The reversal of 14234234024411 is 11442043243241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14234234024411 - 238 = 13959356117467 is a prime.
It is a super-2 number, since 2×142342340244112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14234234024401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117117012205 + 7117117012206.
It is an arithmetic number, because the mean of its divisors is an integer number (7117117012206).
Almost surely, 214234234024411 is an apocalyptic number.
14234234024411 is a deficient number, since it is larger than the sum of its proper divisors (1).
14234234024411 is an equidigital number, since it uses as much as digits as its factorization.
14234234024411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 73728, while the sum is 35.
Adding to 14234234024411 its reverse (11442043243241), we get a palindrome (25676277267652).
The spelling of 14234234024411 in words is "fourteen trillion, two hundred thirty-four billion, two hundred thirty-four million, twenty-four thousand, four hundred eleven".
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