14234999243 has 4 divisors (see below), whose sum is σ = 14249108280. Its totient is φ = 14220890208.

The previous prime is 14234999239. The next prime is 14234999263. The reversal of 14234999243 is 34299943241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34299943241 = 37 ⋅927025493.

It is a cyclic number.

It is not a de Polignac number, because 14234999243 - 2² = 14234999239 is a prime.

It is a super-3 number, since 3×14234999243³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14234999191 and 14234999200.

It is not an unprimeable number, because it can be changed into a prime (14234999263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7053005 + ... + 7055022.

It is an arithmetic number, because the mean of its divisors is an integer number (3562277070).

Almost surely, 2^14234999243 is an apocalyptic number.

14234999243 is a deficient number, since it is larger than the sum of its proper divisors (14109037).

14234999243 is a wasteful number, since it uses less digits than its factorization.

14234999243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14109036.

The product of its digits is 1679616, while the sum is 50.

The spelling of 14234999243 in words is "fourteen billion, two hundred thirty-four million, nine hundred ninety-nine thousand, two hundred forty-three".