14235254051113 has 4 divisors (see below), whose sum is σ = 14984477948560. Its totient is φ = 13486030153668.

The previous prime is 14235254051111. The next prime is 14235254051119. The reversal of 14235254051113 is 31115045253241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14235254051113 - 2¹ = 14235254051111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14235254051111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 374611948695 + ... + 374611948732.

It is an arithmetic number, because the mean of its divisors is an integer number (3746119487140).

Almost surely, 2^{14235254051113} is an apocalyptic number.

It is an amenable number.

14235254051113 is a deficient number, since it is larger than the sum of its proper divisors (749223897447).

14235254051113 is an equidigital number, since it uses as much as digits as its factorization.

14235254051113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 749223897446.

The product of its (nonzero) digits is 72000, while the sum is 37.

The spelling of 14235254051113 in words is "fourteen trillion, two hundred thirty-five billion, two hundred fifty-four million, fifty-one thousand, one hundred thirteen".