Base | Representation |
---|---|
bin | 100000010111100010000000… |
… | …101111100100101100100011 |
3 | 200200000221222202210001022022 |
4 | 200113202000233210230203 |
5 | 122124314112314411342 |
6 | 1222432440305532055 |
7 | 41661530414134136 |
oct | 4027420057445443 |
9 | 620027882701268 |
10 | 142354556013347 |
11 | 413a425676a667 |
12 | 13b7132494402b |
13 | 6157c916cc372 |
14 | 2721dd673a21d |
15 | 116ce7e4c29d2 |
hex | 817880be4b23 |
142354556013347 has 2 divisors, whose sum is σ = 142354556013348. Its totient is φ = 142354556013346.
The previous prime is 142354556013287. The next prime is 142354556013389. The reversal of 142354556013347 is 743310655453241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142354556013347 - 210 = 142354556012323 is a prime.
It is not a weakly prime, because it can be changed into another prime (142354556013247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71177278006673 + 71177278006674.
It is an arithmetic number, because the mean of its divisors is an integer number (71177278006674).
Almost surely, 2142354556013347 is an apocalyptic number.
142354556013347 is a deficient number, since it is larger than the sum of its proper divisors (1).
142354556013347 is an equidigital number, since it uses as much as digits as its factorization.
142354556013347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144000, while the sum is 53.
The spelling of 142354556013347 in words is "one hundred forty-two trillion, three hundred fifty-four billion, five hundred fifty-six million, thirteen thousand, three hundred forty-seven".
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