Base | Representation |
---|---|
bin | 100000010111100010100111… |
… | …101111100010010100100010 |
3 | 200200001000200100222000111102 |
4 | 200113202213233202110202 |
5 | 122124321432320040132 |
6 | 1222433025241514402 |
7 | 41661552550455224 |
oct | 4027424757422442 |
9 | 620030610860442 |
10 | 142355210315042 |
11 | 413a456203716a |
12 | 13b71487aa2a02 |
13 | 615806712b32a |
14 | 27220595ba414 |
15 | 116cebbb69c62 |
hex | 8178a7be2522 |
142355210315042 has 4 divisors (see below), whose sum is σ = 213532815472566. Its totient is φ = 71177605157520.
The previous prime is 142355210314973. The next prime is 142355210315053. The reversal of 142355210315042 is 240513012553241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 106875091717681 + 35480118597361 = 10338041^2 + 5956519^2 .
It is a junction number, because it is equal to n+sod(n) for n = 142355210314987 and 142355210315005.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35588802578759 + ... + 35588802578762.
Almost surely, 2142355210315042 is an apocalyptic number.
142355210315042 is a deficient number, since it is larger than the sum of its proper divisors (71177605157524).
142355210315042 is an equidigital number, since it uses as much as digits as its factorization.
142355210315042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71177605157523.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 142355210315042 its reverse (240513012553241), we get a palindrome (382868222868283).
The spelling of 142355210315042 in words is "one hundred forty-two trillion, three hundred fifty-five billion, two hundred ten million, three hundred fifteen thousand, forty-two".
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