Base | Representation |
---|---|
bin | 1100111100100111011100… |
… | …1111010110000010000100 |
3 | 1212101220101000100210222022 |
4 | 3033021313033112002010 |
5 | 3331213322131130202 |
6 | 50135413015422312 |
7 | 2666324336414666 |
oct | 317116717260204 |
9 | 55356330323868 |
10 | 14235522130052 |
11 | 4599284139963 |
12 | 171ab33684998 |
13 | 7c35336c9992 |
14 | 373008132536 |
15 | 19a472b8cea2 |
hex | cf2773d6084 |
14235522130052 has 12 divisors (see below), whose sum is σ = 25715781912576. Its totient is φ = 6888155869320.
The previous prime is 14235522130003. The next prime is 14235522130069. The reversal of 14235522130052 is 25003122553241.
14235522130052 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 14235522129994 and 14235522130021.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57401298788 + ... + 57401299035.
It is an arithmetic number, because the mean of its divisors is an integer number (2142981826048).
Almost surely, 214235522130052 is an apocalyptic number.
It is an amenable number.
14235522130052 is a deficient number, since it is larger than the sum of its proper divisors (11480259782524).
14235522130052 is a wasteful number, since it uses less digits than its factorization.
14235522130052 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114802597858 (or 114802597856 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 14235522130052 its reverse (25003122553241), we get a palindrome (39238644683293).
The spelling of 14235522130052 in words is "fourteen trillion, two hundred thirty-five billion, five hundred twenty-two million, one hundred thirty thousand, fifty-two".
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