Base | Representation |
---|---|
bin | 100000010111101100000100… |
… | …011011010101001010110011 |
3 | 200200001222212101102022000112 |
4 | 200113230010123111022303 |
5 | 122130003221414441341 |
6 | 1222441424042411535 |
7 | 41662362135035312 |
oct | 4027540433251263 |
9 | 620058771368015 |
10 | 142365355233971 |
11 | 413a8898632991 |
12 | 13b73439500bab |
13 | 6158cc2b58a3c |
14 | 272273caa4279 |
15 | 116d3b2601aeb |
hex | 817b046d52b3 |
142365355233971 has 2 divisors, whose sum is σ = 142365355233972. Its totient is φ = 142365355233970.
The previous prime is 142365355233961. The next prime is 142365355234027. The reversal of 142365355233971 is 179332553563241.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142365355233971 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 142365355233971.
It is not a weakly prime, because it can be changed into another prime (142365355233911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71182677616985 + 71182677616986.
It is an arithmetic number, because the mean of its divisors is an integer number (71182677616986).
Almost surely, 2142365355233971 is an apocalyptic number.
142365355233971 is a deficient number, since it is larger than the sum of its proper divisors (1).
142365355233971 is an equidigital number, since it uses as much as digits as its factorization.
142365355233971 is an evil number, because the sum of its binary digits is even.
The product of its digits is 61236000, while the sum is 59.
The spelling of 142365355233971 in words is "one hundred forty-two trillion, three hundred sixty-five billion, three hundred fifty-five million, two hundred thirty-three thousand, nine hundred seventy-one".
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