Base | Representation |
---|---|
bin | 10100101110001101101… |
… | …010111010010000111011 |
3 | 12001010121202221112121102 |
4 | 110232031222322100323 |
5 | 141312333304324011 |
6 | 3010103122002015 |
7 | 204611214610652 |
oct | 24561552722073 |
9 | 5033552845542 |
10 | 1424011011131 |
11 | 4a9a13101345 |
12 | 1abb964a630b |
13 | a438c28a077 |
14 | 4cccb4b0199 |
15 | 270960c873b |
hex | 14b8daba43b |
1424011011131 has 4 divisors (see below), whose sum is σ = 1424223842664. Its totient is φ = 1423798179600.
The previous prime is 1424011011119. The next prime is 1424011011179. The reversal of 1424011011131 is 1311101104241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1424011011131 - 26 = 1424011011067 is a prime.
It is a super-2 number, since 2×14240110111312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1424011017131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106405730 + ... + 106419111.
It is an arithmetic number, because the mean of its divisors is an integer number (356055960666).
Almost surely, 21424011011131 is an apocalyptic number.
1424011011131 is a deficient number, since it is larger than the sum of its proper divisors (212831533).
1424011011131 is an equidigital number, since it uses as much as digits as its factorization.
1424011011131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 212831532.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 1424011011131 its reverse (1311101104241), we get a palindrome (2735112115372).
The spelling of 1424011011131 in words is "one trillion, four hundred twenty-four billion, eleven million, eleven thousand, one hundred thirty-one".
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