142401110131 has 4 divisors (see below), whose sum is σ = 162744125872. Its totient is φ = 122058094392.

The previous prime is 142401110119. The next prime is 142401110141. The reversal of 142401110131 is 131011104241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142401110131 - 2⁹ = 142401109619 is a prime.

It is a super-2 number, since 2×142401110131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142401110099 and 142401110108.

It is not an unprimeable number, because it can be changed into a prime (142401110141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10171507860 + ... + 10171507873.

It is an arithmetic number, because the mean of its divisors is an integer number (40686031468).

Almost surely, 2^142401110131 is an apocalyptic number.

142401110131 is a deficient number, since it is larger than the sum of its proper divisors (20343015741).

142401110131 is an equidigital number, since it uses as much as digits as its factorization.

142401110131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20343015740.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 142401110131 its reverse (131011104241), we get a palindrome (273412214372).

The spelling of 142401110131 in words is "one hundred forty-two billion, four hundred one million, one hundred ten thousand, one hundred thirty-one".