14241300433 has 2 divisors, whose sum is σ = 14241300434. Its totient is φ = 14241300432.

The previous prime is 14241300373. The next prime is 14241300511. The reversal of 14241300433 is 33400314241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12649051024 + 1592249409 = 112468^2 + 39903^2 .

It is a cyclic number.

It is not a de Polignac number, because 14241300433 - 2¹⁷ = 14241169361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14241300398 and 14241300407.

It is not a weakly prime, because it can be changed into another prime (14241300233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120650216 + 7120650217.

It is an arithmetic number, because the mean of its divisors is an integer number (7120650217).

Almost surely, 2^14241300433 is an apocalyptic number.

It is an amenable number.

14241300433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14241300433 is an equidigital number, since it uses as much as digits as its factorization.

14241300433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 14241300433 its reverse (33400314241), we get a palindrome (47641614674).

The spelling of 14241300433 in words is "fourteen billion, two hundred forty-one million, three hundred thousand, four hundred thirty-three".