Base | Representation |
---|---|
bin | 1100111100111101000110… |
… | …0110011111001001001011 |
3 | 1212102110100222202100120111 |
4 | 3033033101212133021023 |
5 | 3331312222234112134 |
6 | 50142213401135151 |
7 | 2666621340102316 |
oct | 317172146371113 |
9 | 55373328670514 |
10 | 14241333113419 |
11 | 45a07962a9755 |
12 | 172009578a4b7 |
13 | 7c3c4b585789 |
14 | 3733d9bbb97d |
15 | 19a6b2ddac64 |
hex | cf3d199f24b |
14241333113419 has 2 divisors, whose sum is σ = 14241333113420. Its totient is φ = 14241333113418.
The previous prime is 14241333113323. The next prime is 14241333113503. The reversal of 14241333113419 is 91431133314241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14241333113419 - 29 = 14241333112907 is a prime.
It is a super-2 number, since 2×142413331134192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14241333114419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120666556709 + 7120666556710.
It is an arithmetic number, because the mean of its divisors is an integer number (7120666556710).
Almost surely, 214241333113419 is an apocalyptic number.
14241333113419 is a deficient number, since it is larger than the sum of its proper divisors (1).
14241333113419 is an equidigital number, since it uses as much as digits as its factorization.
14241333113419 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 93312, while the sum is 40.
The spelling of 14241333113419 in words is "fourteen trillion, two hundred forty-one billion, three hundred thirty-three million, one hundred thirteen thousand, four hundred nineteen".
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