Base | Representation |
---|---|
bin | 10100101110010101011… |
… | …011100101011100101001 |
3 | 12001010221211221101211211 |
4 | 110232111123211130221 |
5 | 141313120122231213 |
6 | 3010124052353121 |
7 | 204614355364453 |
oct | 24562533453451 |
9 | 5033854841754 |
10 | 1424141211433 |
11 | 4a9a7a64a7a6 |
12 | 1b00120157a1 |
13 | a43b0245a75 |
14 | 4cd008c32d3 |
15 | 270a274653d |
hex | 14b956e5729 |
1424141211433 has 8 divisors (see below), whose sum is σ = 1455052543488. Its totient is φ = 1393255315104.
The previous prime is 1424141211413. The next prime is 1424141211499. The reversal of 1424141211433 is 3341121414241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1424141211433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1424141211395 and 1424141211404.
It is not an unprimeable number, because it can be changed into a prime (1424141211413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6245716 + ... + 6469717.
It is an arithmetic number, because the mean of its divisors is an integer number (181881567936).
Almost surely, 21424141211433 is an apocalyptic number.
It is an amenable number.
1424141211433 is a deficient number, since it is larger than the sum of its proper divisors (30911332055).
1424141211433 is a wasteful number, since it uses less digits than its factorization.
1424141211433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12717863.
The product of its digits is 9216, while the sum is 31.
Adding to 1424141211433 its reverse (3341121414241), we get a palindrome (4765262625674).
The spelling of 1424141211433 in words is "one trillion, four hundred twenty-four billion, one hundred forty-one million, two hundred eleven thousand, four hundred thirty-three".
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