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14241541245433 is a prime number
BaseRepresentation
bin1100111100111101111000…
…0000011100100111111001
31212102110220111101120000121
43033033132000130213321
53331313134024323213
650142250154133241
72666626445146225
oct317173600344771
955373814346017
1014241541245433
1145a0892836387
121720133421221
137c3c82729308
143734196b9785
1519a6c62ee88d
hexcf3de01c9f9

14241541245433 has 2 divisors, whose sum is σ = 14241541245434. Its totient is φ = 14241541245432.

The previous prime is 14241541245427. The next prime is 14241541245469. The reversal of 14241541245433 is 33454214514241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14240298471424 + 1242774009 = 3773632^2 + 35253^2 .

It is a cyclic number.

It is not a de Polignac number, because 14241541245433 - 25 = 14241541245401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14241541245433.

It is not a weakly prime, because it can be changed into another prime (14271541245433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120770622716 + 7120770622717.

It is an arithmetic number, because the mean of its divisors is an integer number (7120770622717).

Almost surely, 214241541245433 is an apocalyptic number.

It is an amenable number.

14241541245433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14241541245433 is an equidigital number, since it uses as much as digits as its factorization.

14241541245433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 921600, while the sum is 43.

Adding to 14241541245433 its reverse (33454214514241), we get a palindrome (47695755759674).

The spelling of 14241541245433 in words is "fourteen trillion, two hundred forty-one billion, five hundred forty-one million, two hundred forty-five thousand, four hundred thirty-three".