Base | Representation |
---|---|
bin | 100000011000011011010001… |
… | …110001100010100011111011 |
3 | 200200020211201001012111202221 |
4 | 200120123101301202203323 |
5 | 122131321030011304111 |
6 | 1222521010004504511 |
7 | 41666135234124214 |
oct | 4030332161424373 |
9 | 620224631174687 |
10 | 142416045025531 |
11 | 4141833a702602 |
12 | 13b812253ab137 |
13 | 6160a107a2444 |
14 | 2724d8ac7240b |
15 | 116e87c7ee371 |
hex | 8186d1c628fb |
142416045025531 has 2 divisors, whose sum is σ = 142416045025532. Its totient is φ = 142416045025530.
The previous prime is 142416045025517. The next prime is 142416045025567. The reversal of 142416045025531 is 135520540614241.
It is a weak prime.
It is an emirp because it is prime and its reverse (135520540614241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 142416045025531 - 243 = 133619952003323 is a prime.
It is a super-2 number, since 2×1424160450255312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (142416045025571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71208022512765 + 71208022512766.
It is an arithmetic number, because the mean of its divisors is an integer number (71208022512766).
Almost surely, 2142416045025531 is an apocalyptic number.
142416045025531 is a deficient number, since it is larger than the sum of its proper divisors (1).
142416045025531 is an equidigital number, since it uses as much as digits as its factorization.
142416045025531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576000, while the sum is 43.
Adding to 142416045025531 its reverse (135520540614241), we get a palindrome (277936585639772).
The spelling of 142416045025531 in words is "one hundred forty-two trillion, four hundred sixteen billion, forty-five million, twenty-five thousand, five hundred thirty-one".
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