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142421113 is a prime number
BaseRepresentation
bin10000111110100…
…10110001111001
3100220222202001001
420133102301321
5242424433423
622044325001
73346362622
oct1037226171
9326882031
10142421113
11734360aa
123b843761
1323677363
1414cb4a49
15c783cad
hex87d2c79

142421113 has 2 divisors, whose sum is σ = 142421114. Its totient is φ = 142421112.

The previous prime is 142421051. The next prime is 142421143. The reversal of 142421113 is 311124241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133818624 + 8602489 = 11568^2 + 2933^2 .

It is an emirp because it is prime and its reverse (311124241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142421113 - 221 = 140323961 is a prime.

It is not a weakly prime, because it can be changed into another prime (142421143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71210556 + 71210557.

It is an arithmetic number, because the mean of its divisors is an integer number (71210557).

Almost surely, 2142421113 is an apocalyptic number.

It is an amenable number.

142421113 is a deficient number, since it is larger than the sum of its proper divisors (1).

142421113 is an equidigital number, since it uses as much as digits as its factorization.

142421113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 192, while the sum is 19.

The square root of 142421113 is about 11934.0317160631. The cubic root of 142421113 is about 522.2255610286.

Adding to 142421113 its reverse (311124241), we get a palindrome (453545354).

The spelling of 142421113 in words is "one hundred forty-two million, four hundred twenty-one thousand, one hundred thirteen".