Base | Representation |
---|---|
bin | 10100101110011011010… |
… | …110000011010100110010 |
3 | 12001011012202121221020022 |
4 | 110232123112003110302 |
5 | 141313321022033432 |
6 | 3010141555043442 |
7 | 204620001600566 |
oct | 24563326032462 |
9 | 5034182557208 |
10 | 1424240424242 |
11 | 4aa020653859 |
12 | 1b003b2a0582 |
13 | a43c797217c |
14 | 4cd0db4b6a6 |
15 | 270ab2e2b12 |
hex | 14b9b583532 |
1424240424242 has 4 divisors (see below), whose sum is σ = 2136360636366. Its totient is φ = 712120212120.
The previous prime is 1424240424241. The next prime is 1424240424311. The reversal of 1424240424242 is 2424240424241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1422726513961 + 1513910281 = 1192781^2 + 38909^2 .
It is not an unprimeable number, because it can be changed into a prime (1424240424241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 356060106059 + ... + 356060106062.
Almost surely, 21424240424242 is an apocalyptic number.
1424240424242 is a deficient number, since it is larger than the sum of its proper divisors (712120212124).
1424240424242 is an equidigital number, since it uses as much as digits as its factorization.
1424240424242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 712120212123.
The product of its (nonzero) digits is 131072, while the sum is 35.
Adding to 1424240424242 its reverse (2424240424241), we get a palindrome (3848480848483).
Subtracting 1424240424242 from its reverse (2424240424241), we obtain a palindrome (999999999999).
The spelling of 1424240424242 in words is "one trillion, four hundred twenty-four billion, two hundred forty million, four hundred twenty-four thousand, two hundred forty-two".
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