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142430022003 = 3277371711673
BaseRepresentation
bin1000010010100101111…
…1011010100101110011
3111121122012012210021010
42010221133122211303
54313144041201003
6145233105402003
713201356132363
oct2045137324563
9447565183233
10142430022003
115544a041695
122372b639303
131057b15c939
146c722649a3
153a89228003
hex21297da973

142430022003 has 8 divisors (see below), whose sum is σ = 189913653648. Its totient is φ = 94949869184.

The previous prime is 142430021977. The next prime is 142430022041. The reversal of 142430022003 is 300220034241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 142430022003 - 29 = 142430021491 is a prime.

It is a super-3 number, since 3×1424300220033 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (142430022043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 772626 + ... + 939047.

It is an arithmetic number, because the mean of its divisors is an integer number (23739206706).

Almost surely, 2142430022003 is an apocalyptic number.

142430022003 is a deficient number, since it is larger than the sum of its proper divisors (47483631645).

142430022003 is a wasteful number, since it uses less digits than its factorization.

142430022003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1739413.

The product of its (nonzero) digits is 1152, while the sum is 21.

Adding to 142430022003 its reverse (300220034241), we get a palindrome (442650056244).

The spelling of 142430022003 in words is "one hundred forty-two billion, four hundred thirty million, twenty-two thousand, three".

Divisors: 1 3 27737 83211 1711673 5135019 47476674001 142430022003